Question

find the equivalent resistance between points a and b​

Answer 1

Answer:

See the answer in the image.

Explanation:

See the answer in the image.

Answer 2

Method:

Step I: Connect an imaginary battery around points A and B

Step II: Write potentials across each resistor.

Step III: Rearrange the circuit.

Step IV: Simplify and solve.

Please refer to the attachment first !!

Between y and x :

Two 16 Ω  resistors are connected in parallel.

$\implies\sf{1 / R_p = 1 / 16 + 1 /16}$

$\implies\sf{1 / R_p = 2 / 16}$

$\implies\sf{R_p = 8 \Omega }$

Similarly,

Between x and o:

$\implies\sf{R_p' = 8 \Omega }$

Between y and o:

Rp and Rp' are connected in series with each other.

$\implies\sf{R_s = R_p + R_p' }$

$\implies\sf{R_s =8 + 8 }$

$\implies\sf{R_s = 16 \Omega }$

Now,

Rs is in parallel with an 16 Ω resistor.

$\implies\sf{1 / R_p' = 1 / 16 + 1 /16}$

$\implies\sf{1 / R_p' = 2 / 16}$

$\implies\sf{R_p' = 8 \Omega }$

Between v and o:

Rp' is in series with an 8Ω resistor.

$\implies\sf{R_{net} =R_p' + R' }$

$\implies\sf{R_{net} =8 + 8}$

$\implies\boxed{\sf{R_{net} =16 \Omega}}$

The net equivalent resistance of the combination is 16Ω.