find the equivalent resistance if the value of R in the circuit is 1.1ohn
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Answer:
0.6 Ohm
Step-by-step explanation:
According to the given fig,
There are 3 parallel combination along with series.
First solving the series combination we get,
Series combination formula,
- R = R1 + R2
Where R is the equivalent resistance of R1 and R2 connected in series.
Thus for 1st row,
- R1 eq = R
- R2 eq = 2R
- R3 eq = 3R
Where R1 eq , R2 eq and R3 eq are the equivalent resistance of first , second and third row.
Now, these equivalent resistors are in parallel combination.
Parallel combination formula,
- 1/R' eq = 1/R1 + 1/R2
Where R' eq is the equivalent resistance of R1 and R2 connected in parallel.
Thus final combination of resistance is,
- 1/R' = 1/R + 1/2R + 1/3R
Where R' is the final equivalent resistance.
- 1/R' =6R^2+3R^2+2R^2/3R×2R×R
- 1/R' = 11R^2/6R^3
- 1/R' = 11/6R
- R' = 6R/11
Putting the values we get,
- R' = 6×1.1/11
- R' = 6.6/11
- R' = 0.6 ohm
Thus final equivalent resistance is 0.6 ohm.
janhvi39:
if instead of 1.1ohm if its 11ohm then what's the answer
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