Find the equivalent resistance of resistors in the circuit given below
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R1 and R2 are in series as well R3 and R4 are in series since here from A to B (via C) the current remains undivided similarly from A to B ( via D) the current remains undivided.
Resistance of R1 and R2 = 4ohm+4ohm = 8 ohm
Resistance of R3 and R4 = 4ohm+4ohm = 8 ohm
combination of R1 -R2 (say R) // combination of R3 - R4 (say R5)
Equivalent resistance = (R×R5) / (R+R5)
= (8×8)/(8+8)
= 64 /16
= 4 ohm
So total resistance is 4 ohm . Ans
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