Question

Find the equivalent resistance of the following circuit- ​

Answer 1

Answer:

The two 1Ω resistances are in parallel. So, equivalent resistance is  

1×1/1+1 Ω=  1/2Ω

Similarly, the two 2Ω resistances are in parallel. So equivalent resistance is  

2×2/2+2 Ω=1Ω

Now these 1Ωand  1/ 2  Ω resistances are in series with the two 3Ω resistances.  

So the equivalent resistance of the circuit is (1+  1/2  +3+3)Ω

  R= 15 /2 Ω

Answer 2

Answer:

9 ohm

Explanation:

let, R1 = 3 ohm, R2= 3ohm .R3 = 2ohm .R4 = 2 ohm., R5 = 1ohm R6= 1ohm.

here R1, R2 are in series so.

R *be = R1+ R2 = 3 + 3 = 6 ohm. ---------equation 1

here R3 and R4 are in parallel so,

R° = 1÷ R3 +1 ÷ R4= 1 /2 + 1/ 2= 1 ohm ----------equation 2

here R5 and R6 are in parallel....

so, R• = 1 / R5 + 1/R6 = 1/1 + 1/1 = 2 ohm --- equation 3 ..

so now equation 1 , equation 2 and equation 3 are in series so.

Rtotal = R* + R°+ R• = 6 + 1 + 2= 9 ohm...

9 ohm is the total resistance in this circuit.

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