Find the equivalent resistance of the following circuit between A and B.
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R1 = 2Ω, R2 = 10 Ω, R3 = 4 Ω, R4 = 2.5 Ω, R5 = 3.5 Ω
R1 and R2 are in series
=> equivalent resistance = R6 = R1 + R2 = 2 Ω + 10 Ω = 12 Ω
R4 and R5 are series
=> equivalent resistance = R7 = R4 + R5 = 2.5 Ω + 3.5 Ω = 6 Ω
R6, R7 and R3 are parallel => (1/R) = (1/R6) + (1/R7) + (1/R3)
= (1/12) + (1/6) + (1/4)
= 1/2
Equivalent resistance R = 2 Ω
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