Find the equivalent resistance of the given circuit
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Answer:
4.54
Explanation:
See the circuit carefully
R2 , R3 & R4 are in parallel combination
So by applying formla of parallel equivalent resistance
1/R2 + 1/R3 + 1/R4
it comes 11/6
Then resultant resistance and R1 & R5 are in series combination so by applying series equivalent formula you found final resistant 50/11 means 4.54
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