Question

Find the equivalent resistance of the network shown in figure between the points a and b.
i can't attach the file.... it's a parallel circuit, three resistors in a wire and and 2 wires are around it, one above and one down.

Answer 1

Explanation:

The two resistances R1 and R2 of 4 ohms are in series therefore their equivalent resistance,

R' = 4 Ω + 4 Ω = 8 Ω

Now the resistances R', R3 and R4 are in parallel so the equivalent resistance of the circuit would be.

Therefore the equivalent resistance between the two points A and B in the given circuit is 1.85 Ω.