Find the equivalent resistance of three resistors of resistance 10 OHM , 20OHM and 40OHM when connected in (1) series(2) parallel?
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Answer:
in series-
R= r1 + r2 + r3
R=10+200+400
R=610 ohm
in parallel-
R=1/r1 + 1/r2 + 1/r3
R= 1/10 + 1/200 + 1/400
R= 0.1 + 0.005 + 0.0025
R= 0.1075 ohm
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