find the equivalent resistance of two resistors connected in parallel,each of having 1 ohm and 10^6 ohm respectively.If in fraction please write it also.
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For two resistors in parellel arrangement
Equivalent resistance = (R₁ × R₂) / (R₁ + R₂)
= (10⁶ Ω × 1 Ω) / (10⁶ Ω + 1 Ω)
≈ (10⁶ / 10⁶) Ω …………[∵ 10⁶ Ω >>> 1 Ω]
≈ 1 Ω
Equivalent resistance is approximately 1 Ω
Equivalent resistance = (R₁ × R₂) / (R₁ + R₂)
= (10⁶ Ω × 1 Ω) / (10⁶ Ω + 1 Ω)
≈ (10⁶ / 10⁶) Ω …………[∵ 10⁶ Ω >>> 1 Ω]
≈ 1 Ω
Equivalent resistance is approximately 1 Ω
vishalkhurana:
Sorry but the EQ. Resistance will be less than one
It will be nearly equal to 1
Ya but not exactly
the answer is 0.999999
which is considered equal to 1
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