find the eqution of line through point (3,2) which maks angle45°with the line x-2y-3
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slope (m)=tan(theta)
=tan(45°)
= 1
(3;2) point i.e, x1=3;y1=2
formula:
x-x1=m(y-y1)
x-3= 1(y-2)
x-3= y-2
x-3-y+2=0
x-y-1 =0
is the equation of required line
=tan(45°)
= 1
(3;2) point i.e, x1=3;y1=2
formula:
x-x1=m(y-y1)
x-3= 1(y-2)
x-3= y-2
x-3-y+2=0
x-y-1 =0
is the equation of required line
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