Question

Find the eqution of tangent to the curve y=x^2-3x+5 at the point (1,3)

Answer 1

dy/dx=2x-3=slope of tangent at (1,3)

slope=-1

so

$\frac{y - 3}{x - 1} = - 1$

y-3=1-x

y+x=4

Answer 2

Answer:

x + y - 4 = 0

Step-by-step explanation:

Please find the attached image.