Question

find the error in the above python program. it is to find out whether the no is even or odd??

Answer 1

The correct code is:-

n=int(input("enter number"))

if(n%2==0):

print("even")

else:

print("odd")

.

.

.

hope it will help you mate..

Answer 2

Answer:

n= int(input("Enter a no."))

if n%2==0:

  print("n is even")

else:

  print("n is odd")