Question

find the escape velocity of a body from the surface of mars . [ radius of mars= 3392 km, g mars = 3.724m/s^2

Answer 1

Answer:

Mmars = 6.42 x 1023 kg

    Rmars = 3398 km = 3.398 x 106 m

    vescape = (2 x 6.67 x 10-11 N m2 kg-3 x 6.42 x 1023 kg / 3.398 x 106 m)0.5

    vescape= 5.02 x 104 m/s=5.02 km/

Explanation:

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Answer 2

Answer:

Mmars=6.42×123 Kg

Rmars=3398km=3.398×106m

Vescape=2×6.67×10-11N m2 kg-3×6.42×1023kg/3.398×106m) 0.5

vescape=5.02×104 m/s

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