Find the evolute of hyperbola
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Ànswer:
The evolute of a hyperbola with parametric equations
x = acosht
(1)
y = bsinht
(2)
is
x_e = ((a^2+b^2))/acosh^3t
(3)
y_e = -((a^2+b^2))/bsinh^3t,
(4)
which is similar to a Lamé curve, but with a minus sign. Eliminating t gives the implicit Cartesian equation for the evolute as
(ax)^(2/3)-(by)^(2/3)=(a^2+b^2)^(2/3).
(5)
From a point between the two branches of the evolute, two normals can be drawn to the hyperbola. However, from a point beyond the evolute, four normals can be drawn.
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