Question

find the excess pressure inside a soap bubble of radius 0.5mm the surface tension of soap solution is 2.5× 10^2N/m​

Answer 1

Answer:

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Explanation:

The excess pressure is calculated as ΔP=

r

4T

ΔP=

0.5×10

−2

4×25×10

−3

=20N/m

2

1Pa=1N/m

2

⇒ΔP=20Pa

Option C is correct.