Question

Find the excluded values of x^2+6x+8÷(x^2+x-2)

Answer 1

x^2+6x+8÷(x^2+x-2)

x^2+2x+4x+8÷(x^2+2x-x-2)

(x(x+2)+4(x+2))÷(x(x+2)-1(x+2))

(x+2)(x+4)÷(x-1)(x+2)

(x+4)÷(x-1)

Answer 2

Answer:

1, -2

Step-by-step explanation:

= x²+6x-8 / x²+x-2 = p(x) / q(x)

Excluded value for p(x)/q(x), q(x)=0

= x²-x+2x-2

= x(x-1)+2(x-1)

= (x-1)(x+2) = 0

(x-1) ⇒ x = 1, (x+2) ⇒ x = -2

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