Question

find the expansion of (2x-1/3y)^3​

Answer 1

Answer:

(a-b)³ = a³-b³-3ab(a-b)

(2x-1/3y)³

=(2x-1)³/(3y)³

= [8x³-1-3(2x)(1)(2x-1)]/27y³

= (8x³-1-12x²+6x)/27y³

Step-by-step explanation:

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Answer 2

Answer:

(2x−3y)

3

=(2x)

3

−3(2x)

2

(3y)+3(2x)(3y)

2

−(3y)

3

=8x

3

−36x

2

y+54xy

2

−27y

3

Step-by-step explanation:

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