find the expansion of (2x-1/3y)^3
Answers
Answered by
5
Answer:
(a-b)³ = a³-b³-3ab(a-b)
(2x-1/3y)³
=(2x-1)³/(3y)³
= [8x³-1-3(2x)(1)(2x-1)]/27y³
= (8x³-1-12x²+6x)/27y³
Step-by-step explanation:
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Answered by
2
Answer:
(2x−3y)
3
=(2x)
3
−3(2x)
2
(3y)+3(2x)(3y)
2
−(3y)
3
=8x
3
−36x
2
y+54xy
2
−27y
3
Step-by-step explanation:
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