Question

Find The Expansion Of (3xy.2x/y)5 by use of binomial theorem

Answer 1

Answer:

$(3xy - \frac{2x}{y} ) {}^{5} = \sum_{k = 0} ^{5} \binom{5}{k} (3xy) {}^{k} ( \frac{ - 2x}{y} ) {}^{5 - k}$