Find the expansion of (x+y-1)³
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Answer:
Step-by-step explanation:
Using the identity (a+b+c)^2=a^2+b^2+c^2+2(ab+bc+ac)
Here,
a=x
b=y
c=-1
APPLYING THE IDENTITY, [(a+b+c)^2=a^2+b^2+c^2+2(ab+bc+ac)]
x^2 + y^2 + 1 + 2(xy+(-y)+(-x))
x^2 + y^2 + 1 + 2(xy-y-x)
OR,
x^2 + y^2 + 1 + 2xy- 2y- 2x
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