Question

find the expansion of (x+y-1)³. please solve with explanation..​

Answer 1

Answer:

I hope it helps you

Step-by-step explanation:

Thank You

Answer 2

Answer:

Step-by-step explanation:

Formula: (a+b+c)^3=a^3+b^3+c^3+3(a+b)(b+c)(a+c)

in the problem mentioned, a=x, b=y and c= -1

therefore, using the formula:

(x+y-1)^3 = x^3 + y^3 + (-1)^3 + [3(x+y) (y-1) (x-1)]

(x+y-1)^3 = x^3 + y^3 -1 +[3(x+y) (xy -y -x +1)]

(x+y-1)^3 = x^3 + y^3 -1 +[3 (x^2 y -xy -x^2 +x + x y^2 -y^2 -xy +y]

(x+y-1)^3 = x^3 + y^3 -1 + 3x^2 y -3xy -3x^2 +3x + 3x y^2 -3y^2 -3xy +3y