find the expansions of the (x+5y-4) ^3
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Answer:
x+y+2)
3
Let us simplify the expression
By using the formula, we get
(x+y+2)
3
=[(x+y)+2]
3
=(x+y)
3
+(2)
3
+3(x+y)(2)(x+y+2)
=x
3
+y
3
+3x
2
y+3xy
2
+8+6(x+y)[(x+y)+2]
=x
3
+y
3
+3x
2
y+3xy
2
+8+6(x+y)
2
+12(x+y)
=x
3
+y
3
+3x
y
+3xy
2
+8+6(x
2
+y
2
+2xy)+12x+12y
=x
3
+y
3
+3x
2
y+3xy
2
+8+6x
2
+6y
2
+12xy+12x+12y
=x
3
+y
3
+3x
2
y+3xy
2
+8+6x
2
+6y
2
+12x+12y+12xy
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