Find the expectation value of the position of a particle trapped in a box of
length 0.1nm
Expectation value of the position of the particle is
L
x 1412 dx
2.
2 뇌
x sin²
310X
dz
sin
-
COS
L4
8
21
0.1
= 0.05nm
2
2
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Explanation:
check out the attachment(see properly)
probably you are studying engineering physics right?
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