Question

find the expression for
1.Time of flight
2.Horizontal Range.
3.Maximum height for a body projected oncler gravity at some angle & from the Horzontalo.
Also show that its paths is a parabole.​

Answer 1

Answer:

may be my answer helps you

Explanation:

1. answer: To find the time of flight, determine the time the projectile takes to reach maximum height. The time of flight is just double the maximum-height time. At maximum height, vy = 0. The time of flight is also determined solely by the initial velocity in the y direction and the acceleration due to gravity.

2. answer: The range (R) of the projectile is the horizontal distance it travels during the motion. Using this equation vertically, we have that a = -g (the acceleration due to gravity) and the initial velocity in the vertical direction is usina (by resolving). Hence: y = utsina - ½ gt2 (1)

3. answer: Two bodies are thrown from the same point with the same velocity of 50ms−1. If their angles of projection are complimentary to each other