Question

find the expression for a velocity of a partical in vcm at different position​

Answer 1

Answer:

Let a particle make an angle £ with the downward vertical while executing a vertical circle. Then its equation of motion is: T- mgcos£= mv^2/r, T= tension in the string, m= mass of the particle, v= speed, r= radius of the circle. Assuming that the bottom point of the circle is the zero plane of P.E., applying conservation of mechanical energy mv^2/2+mgr(1-cos£)= 0.5*m(v_b)^2 From this equation v^2= (v_b)^2–2gr(1-cos£). Using this equation one can find the velocity of a particle executing vertical circular motion.