find the expression for acceleration due to gravity at a height h above the Earth surface.
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You have a formula,
gh=g[1−(2h/R)]gh=g[1−(2h/R)]
Where, gh=gravity at height h meters.
Now, you just need to put all the values given and change gh according to the relation provided.
The question says, gh is 96% less than g, or we can also say it as, GH is 4% that of g. Now put GH=4% of g.
You get an equation,
h=[1−0.04]R/2h=[1−0.04]R/2
Solve the equation to find h and you will get the height at which the gravity will become 96% less.
Hope this answer helps you.
gh=g[1−(2h/R)]gh=g[1−(2h/R)]
Where, gh=gravity at height h meters.
Now, you just need to put all the values given and change gh according to the relation provided.
The question says, gh is 96% less than g, or we can also say it as, GH is 4% that of g. Now put GH=4% of g.
You get an equation,
h=[1−0.04]R/2h=[1−0.04]R/2
Solve the equation to find h and you will get the height at which the gravity will become 96% less.
Hope this answer helps you.
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