find the expression for moment of inertia of a cricket ball of mass M and radius R about its diameter.
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Given, Moment of inertia(MOI) of sphere about its diameter=52MR2=I
Using Parallel axis theorem, I=Icm+Mx2 where Icm is MOI about centre of mass x is distance between centre of mass and axis of rotation.
⇒MOI of system=2×52MR2+2×(52MR2+MR2)=518MR2=9I
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