Question

find the expression of (-2x+3y+22)^2​

Answer 1

Answer:

=4$x^{2}$-12xy+$9y^{2}$-88x+132y+484.

Step-by-step explanation:

(-2x+3y+22)(-2x+3y+22)

= -2x(-2x+3y+22)+3y(-2x+3y+22)+22(-2x+3y+22)

= 4$x^{2}$-6xy-44x-6xy+9$y^{2}$ +66y -44x+66y+484

=4$x^{2}$-12xy+$9y^{2}$-88x+132y+484.