find the extercal work done by the system in kcal when 20cal of heat is supplied to the system the increse in the internal energy is 8400J(J=4200J/kcal)
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find the extercal work done by the system in kcal when 20cal of heat is supplied to the system the increse in the internal energy is 8400J(J=4200J/kcal)
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Answer: Given that ,
dQ=20kcal (convert kcal into J), dU= 8400J,
Explanation:
dQ=dU+ dW
dW= dQ-dU (Q=20×4200=84000J)
dW= 84000-8400
=75600J
dW= 75600÷4200
dW= 18 Kcal
The external work done by the system is 18 Kcal
The Work done is positive
Hope it helps you
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