Question

Find the external work done by the system in kcal,when 20 kcal of heat is supplied to the system the increase in the internal energy is 8400J

Answer 1

According to 1st law of thermodynamics
dU = q + W

8.4 kJ = (20 × 4.2 kJ) + W
W = 8.4 kJ - 84 kJ
W = -75.6 kJ
W = -75.6/4.2 = -18 kcal

Work done by system is 18 kcal

Answer 2

Explanation:

According to 1st law of thermodynamics

dU = q + W

8.4 kJ = (20 × 4.2 kJ) + W

W = 8.4 kJ - 84 kJ

W = -75.6 kJ

W = -75.6/4.2 = -18 kcal

Work done by system is 18 kcal

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