Find the external work done by the system in kcal,when 20 kcal of heat is supplied to the system the increase in the internal energy is 8400J
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Answered by
83
According to 1st law of thermodynamics
dU = q + W
8.4 kJ = (20 × 4.2 kJ) + W
W = 8.4 kJ - 84 kJ
W = -75.6 kJ
W = -75.6/4.2 = -18 kcal
Work done by system is 18 kcal
dU = q + W
8.4 kJ = (20 × 4.2 kJ) + W
W = 8.4 kJ - 84 kJ
W = -75.6 kJ
W = -75.6/4.2 = -18 kcal
Work done by system is 18 kcal
Answered by
7
Explanation:
According to 1st law of thermodynamics
dU = q + W
8.4 kJ = (20 × 4.2 kJ) + W
W = 8.4 kJ - 84 kJ
W = -75.6 kJ
W = -75.6/4.2 = -18 kcal
Work done by system is 18 kcal
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