find the extrem values of the following y=X3-6x2+9x-8
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Answer:Given:
y
=
x
3
−
6
x
2
+
9
x
−
8
.
We first take the derivative of this function.
y
'
=
3
x
2
−
12
x
+
9
Now, we find the zeros of
y
'
. Using quadratic formula, we get,
x
=
12
±
√
144
−
4
⋅
3
⋅
9
6
=
12
±
√
36
6
=
12
±
6
6
∴
x
1
=
12
+
6
6
=
3
∴
x
2
=
12
−
6
6
=
1
Step-by-step explanation:
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