Math, asked by chahatt076, 7 hours ago

find the extrem values of the following y=X3-6x2+9x-8​

Answers

Answered by singhmahima262
2

Answer:Given:

y

=

x

3

6

x

2

+

9

x

8

.

We first take the derivative of this function.

y

'

=

3

x

2

12

x

+

9

Now, we find the zeros of

y

'

. Using quadratic formula, we get,

x

=

12

±

144

4

3

9

6

=

12

±

36

6

=

12

±

6

6

x

1

=

12

+

6

6

=

3

x

2

=

12

6

6

=

1

Step-by-step explanation:

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