Math, asked by Khushibrainly, 8 months ago

find the factor of 1 upon 2 x square - 3 x plus 4​

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Answered by harshit88384
6

Answer:

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Answered by Anonymous
9

Answer:

\Huge\bold{\underline{\underline{\green{Solution:-}}}}

 {\frac{1}{2}x}^{2}  - 3x + 4 = 0

 \frac{ {x}^{2}  - 6x + 8}{2}   = 0

 {x}^{2}  - 6x  + 8 = 0 \times 2

 {x}^{2}  - 6x + 8 = 0

 {x}^{2}  - 4x - 2x  + 8 = 0

x(x - 4) - 2(x - 4) = 0

(x - 2)(x - 4)

x - 4 = 0  \:  \: =  > x =  4

x - 2 = 0 \:  \:  =  > x = 2

value \: of \: x \: are \: 4 \: and \: 2

\small\blue{\mid{\fbox{\tt{Hope it's helpful uh ♡♡}}\mid}}

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