Question

find the factor of 42 - x- x ^ 2​

Answer 1

$\huge \mathfrak \red{answer}$

$\bf{ \underline{ \boxed{ \green{ \tt{(x = - 7) \: or \: (x = 6 \: )}}}}}}$

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$\sf \huge \underline{Question}$

$\rm{42 - x - {x}^{2}}$

$\rm{ - {x}^{2} - x + 42}$

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step by step explanation:

$\sf \red{⟹ \: - {x}^{2} - x + 42}$

$\sf \blue{⟹ \: - {x}^{2} - 7x + 6x + 42}$

$\sf \pink{⟹ \: - x(x + 7) + 6(x + 7)}$

$\sf \orange{⟹ \: (x + 7)(6 - x)}$

$\sf \red{⟹ \: x = - 7 \: or \: x = 6}$

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i hope it's help uh

Answer 2

Answer:

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$\color{red}\huge{\underline{\underline{\mathfrak{Question:-}}}}$

find the factor of 42 - x- x ^ 2

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$\color{blue}\huge{\underline{\underline{\mathfrak{Answer}}}}$

To find:- Factor of 42-x-x²

It can also be written as

-x²-x+42

Let it be equal as zero

So,

-x²-x+42=0

Or

x²+x-42=0

The two numbers whose sum is 1 and product is 42 are 7 and -6

Now

x²-6x+7x-42=0

x(x-6)+7(x-6)=0

Here (x-6) can be taken as common

So,

(x-6)(x+7)=0

So,

(x-6)=0 and (x+7)=0

x=6 and x=-7

Hence the factors of 42 - x- x ^ 2 are '6' and '-7'

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