Question

find the factor of 81x²-1


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Answer 1

Step-by-step explanation:

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Answer 2

Given:

A polynomial 81x² - 1.

To find:

The factor of 81x² - 1.

Solution:

To answer this question, first of all, we should know one of the algebraic quantities which is

${a}^{2} - {b}^{2} = (a - b)(a + b)$

Now, as given,

we have a polynomial

$81x² - 1$

$= {(9x)}^{2} - {(1)}^{2}$

(as the square of 9 is 81)

This can be written as

$(9x + 1)(9x - 1)$

( from the above mentioned algebraic quantity)

Hence, the factors of 81x² - 1 are 9x + 1 and 9x - 1.