Math, asked by Anonymous, 10 months ago

find the factor of a²(b+c)+b²(c+a)+c²(a+b)-2b²c

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Answered by ananya770

0

Answer:

Plz Mark as BRAINLIEST

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Answered by simpi4114

1

Answer:

a2(b+c)+b2(a-c)+c2(a+b)

Step-by-step explanation:

a2(b+c)+b2(a-c)+c2(a+b) =a2(b+c)+B2(c+a)+c2(a+b)-2b2c

=a2b+a2c+b2c+b2a+c2a+c2b-2b2c

=a2b+a2c+b2a+c2a+c2b-b2c

=a2(b+c)+B2(a-c)+c2(a+b)

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