find the factor of a²(b+c)+b²(c+a)+c²(a+b)-2b²c
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Answer:
a2(b+c)+b2(a-c)+c2(a+b)
Step-by-step explanation:
a2(b+c)+b2(a-c)+c2(a+b) =a2(b+c)+B2(c+a)+c2(a+b)-2b2c
=a2b+a2c+b2c+b2a+c2a+c2b-2b2c
=a2b+a2c+b2a+c2a+c2b-b2c
=a2(b+c)+B2(a-c)+c2(a+b)
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