Question

find the factor of the following polynomials 3(4x+5)2-2(4x+5)-1​

Answer 1

Answer:

find the factor of the following polynomials 3(4x+5)2-2(4x+5)-1

Answer 2

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$\: \clubsuit \large \green{ \bold{ \underline{ \: correct \: answers}}}$

$\: \: \\ \implies \displaystyle \sf{3 {(4x + 5)}^{2} - 2(4x + 5) - 1 = 0}$

$\: \\ \: \implies \displaystyle \sf{3( 16{x}^{2} + 25 + 40x) - 8x - 10 - 1 = 0}$

$\: \\ \implies \displaystyle \sf{48 {x}^{2} + 75 + 120x - 8x - 11 = 0}$

$\: \: \implies \displaystyle \sf{48 {x}^{2} + 112x + 64 = 0}$

$\: \: \implies \displaystyle \sf{24 {x}^{2} + 56x + 32 = 0}$

$\: \: \\ \implies \displaystyle \sf{12 {x}^{2} + 28x + 16 = 0}$

$\: \\ \implies \displaystyle \sf{6 {x}^{2} + 14x + 8 = 0}$

$\: \: \ \\ \implies \displaystyle \sf{3 {x}^{2} + 7x + 4 = 0}$

$\: \: \: \\ \implies \displaystyle \sf{3 {x}^{2} + 3x + 4x + 4 = 0}$

$\: \: \\ \implies \displaystyle \sf{3x(x + 1) + 4(x + 1) = 0}$

$\: \\ \implies \displaystyle \sf{(x + 1)(3x + 4) = 0}$

$\: \: \ \\ \implies \displaystyle \sf{x = - 1 \: and \: x = - \frac{4}{3} }$

$\: \: \bigstar \large\blue{ \bold{ \boxed{ \underline{ \bf \: the \: value \: of \: x \: will \: be \: x = - 1 \: and \: x = \frac{ - 4}{3} }}}}$