Math, asked by ashwinipandharpure20, 2 months ago

find the factor of x^3 - 64y^3​

Answers

Answered by shivajikaithi
1

Answer:

Algebra Examples

Algebra ExamplesRewrite 64y3 64 y 3 as (4y)3 ( 4 y ) 3 . Since both terms are perfect cubes, factor using the difference of cubes formula, a3−b3=(a−b)(a2+ab+b2) a 3 - b 3 = ( a - b ) ( a 2 + a b + b 2 ) where a=x and b=4y b = 4 y . Simplify. Multiply 4 4 by −1 - 1 .

Answered by AbhinavRocks10
3

Step-by-step explanation:

Algebra Examples

Rewrite 64y3 64 y 3 as (4y)3 ( 4 y ) 3 . Since both terms are perfect cubes, factor using the difference of cubes formula, a3−b3=(a−b)(a2+ab+b2) a 3 - b 3 = ( a - b ) ( a 2 + a b + b 2 ) where a=x and b=4y b = 4 y . Simplify. Multiply 4 4 by −1 - 1 .

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