Math, asked by priy11, 1 year ago

find the factor of y^3+y^2+y+1​

Answers

Answered by patilcourt
6

Answer:

Step-by-step explanation:f(y)=y³+y²+y+1=0

f'(y)=3y²+2y+1=0

=3y²+3y-y+1=0

3y(y+1)-1(y+1)=0

3y-1=0,y+1=0

y=1/3,y=-1

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