Question

Find the factor
x^2-3xy+3y^2+9x-9y+18=0​

Answer 1

Answer:

check out the answer

Step-by-step explanation:

The factorized expression is x(x-3y+9)+3y(y-3)+18x(x−3y+9)+3y(y−3)+18

Therefore x^2-3xy+3y^2+9x-9y+18=x(x-3y+9)+3y(y-3)+18x

2

−3xy+3y

2

+9x−9y+18=x(x−3y+9)+3y(y−3)+18