Question

Find the factor:-
y2 - 7x + 7y + x2 + 3xy - 8 = 0

Answer 1

Step-by-step explanation:

x^2 + 3xy + 2y^2 + 5x + 7y + 6 => (x + y) is a good candid for factor try to re write:

= x^2 + 2xy + y^2 + xy + y^2 + 3x + 3y + 2x + 4y + 6 => factor:

= (x + y)^2 + y(x + y) + 3(x + y) + 2(x + 2y + 3) => first 3 terms have (x + y) as common factor:

= (x + y)[x + y + y + 3] + 2(x + 2y + 3) => simplify:

= (x + y)(x + 2y + 3) + 2(x + 2y + 3) => worked out nicely: (x + 2y + 3) common factor:

Answer 2

x^2 + 3xy + 2y^2 + 5x + 7y + 6 => (x + y) is a good candid for factor try to re write:

= x^2 + 2xy + y^2 + xy + y^2 + 3x + 3y + 2x + 4y + 6 => factor:

= (x + y)^2 + y(x + y) + 3(x + y) + 2(x + 2y + 3) => first 3 terms have (x + y) as common factor:

= (x + y)[x + y + y + 3] + 2(x + 2y + 3) => simplify:

= (x + y)(x + 2y + 3) + 2(x + 2y + 3) => worked out nicely: (x + 2y + 3) common factor:

= (x + 2y + 3)(x + y + 2)


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