Question

find the factorisation. (2a+3b+4c)2
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Answer 1

Answer:

4a+6b+8c............

Answer 2

Answer:

Question :-

➠ (2a + 3b + 4c)²

Formula used :-

➪ (a + b + c)²

➭ a² + b² + c² + 2ab + 2bc + 2ca

Answer :-

➠ (2a + 3b+ 4c)²

➻ (2a)² + (3b)² + (4c)² + 2 × 2a × 3b + 2 × 3b × 4c + 2 × 4c × 2a

➻ 4a² + 9b² + 16c² + 12ab + 24bc + 16ca

∴ The value of (2a + 3b + 4c)² is 4a² + 9b² + 16c² + 12ab + 24bc + 16ca