Question

find the factors cubic equation m^3+6m^2+9m+4​

Answer 1

Step-by-step explanation:

Step by step solution :

STEP

1

:

Equation at the end of step 1

(((m3) + (2•3m2)) + 9m) + 4 = 0

STEP2:

Checking for a perfect cube

2.1 m3+6m2+9m+4 is not a perfect cube

Trying to factor by pulling out :

2.2 Factoring: m3+6m2+9m+4

Thoughtfully split the expression at hand into groups, each group having two terms :

Group 1: 9m+4

Group 2: 6m2+m3

Pull out from each group separately :

Group 1: (9m+4) • (1)

Group 2: (m+6) • (m2)

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Answer 2

$\huge\mathbb\color{teal}ANSWER:-$

$m^3 + 6m^2 + 9m + 4$

$m^3 + 5m^2 + m^2 + 4m + 5m + 4$

$(m^3 + 5m^2 + 4m)+(m^2 + 5m + 4)$

$m(m^2 + 5m + 4) + 1(m^2 + 5m + 4)$

$(m + 1)(m^2 + 5m + 4)$

$(m + 1)[m^2 + 4m + m + 4]$

$(m + 1)[m(m + 4) + 1(m + 4)]$

$(m + 1)(m + 1)(m + 4)$

$(m + 1)^2(m + 4)$