Math, asked by TarunKumarCS, 5 hours ago

Find the factors fo 3a²+35a-12 using splitting the middle term. Give full steps and do not put irrelevent answers. I will mark the best answer as Brainliest and i will report any answer that is not relevent

Answers

Answered by dineshseethalam04
1

Answer:

3a²+35a-12=0

3a²+36a-a-12=0

3a(a+12) -1(a+12)=0

(a+12) (3a-1)=0

a+12=0 , a=-12

3a-1=0 , 3a=1 , a=1/3

Answered by aneesh97127
0

Answer:

( 3a - 1 ) ( a + 12 )

Step-by-step explanation:

3a² + 35a - 12

= 3a² + 36a - a - 12

= 3a ( a + 12 ) - 1 ( a + 12 )

= ( 3a - 1 ) ( a + 12 )

here is a trick if you want to find numbers

then additional of two numbers is cofficient of middle term

and multiplication of two numbers is product of cofficient of two terms

here additional of two numbers = 35

multiplication of two numbers = -36

so two numbers are solving above case are 36, -1

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