Question

Find the factors ob polynomial x2 -3x -28​

Answer 1

Step-by-step explanation:

f(x) = x² - 3x - 28

To find zero

put f(x) = 0

x² - 3x - 28 = 0

x² - 7x + 4x - 28 = 0

x ( x - 7 ) + 4 (x  - 7 ) = 0

( x - 7 )( x + 4 ) = 0

x = 7 & -4

let α = 7 and β = -4

Now to verify the relation

sum of zeroes = α + β = 7 + (-4) = 3

\frac{-coefficient\:of\:x}{Coefficient\:of\:x^2}=\frac{-(-3)}{1}=3Coefficientofx2−coefficientofx=1−(−3)=3

Product of zeroes = α . β = 7 × (-4) = -28

\frac{constant\:term}{Coefficient\:of\:x^2}=\frac{-28}{1}=-28Coefficientofx2constantterm=1−28=−28

sum of zeroes =  \frac{-coefficient\:of\:x}{Coefficient\:of\:x^2}Coefficientofx2−coefficientofx

Product of zeroes =  \frac{constant\:term}{Coefficient\:of\:x^2}Coefficientofx2constantterm

Answer 2

Step-by-step explanation:

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