Math, asked by avigyansarkar65, 6 months ago

Find the factors of =121mn(m²-n)

Answers

Answered by atraye28

0

Answer:

m−11,m+11.

Step-by-step explanation:

We have the identity (a−b)(a+b)=a2−b2

We need to simplify by using identity m2−121=(m−11)(m+11)

The factors are m−11,m+11.

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