Question

Find the factors of 16x^2+40xy+25y^2-4​

Answer 1

Starting with the trinomial

16

x

2

+

40

x

y

+

25

y

2

we first note that the first and last terms are perfect squares, so we see that

16

x

2

+

40

x

y

+

25

y

2

=

(

4

x

+

5

y

)

(

4

x

+

5

y

)

=

(

4

x

+

5

y

)

2

Answer 2

The answer is = (4x + 5y)(4x + 5y)

Step-by-step explanation:

$16x^2+40xy+25y^2 \\ \\ = = > \: \: \: {(4x)}^{2} + 2 \times 4x \times 5y + {(5y)}^{2} \\ \\ = = > \: \: \: \: \: \: {(4x + 5y)}^{2} \\ \\ = = > \: \: \: (4x + 5y)(4x + 5y)$

.

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