Question

find the factors of (16y^2-1)+(1-4y)^2​

Answer 1

(16y^2 -1 ) + ( 1 - 4y )^2

= ( 16y^2 - 1 ) + ( 1 - 4y ) × ( 1 - 4y )

= ( 16y^2 - 1 ) + 1( 1- 4y )- 4y ( 1 - 4y )

= ( 16y^2 - 1 ) + 1 - 4y - 4y + 16y^2

= 16y^2 - 1+ 1 - 8y + 16y^2

= 16y^2 + 16y^2 - 8y + 1 - 1

= 32y^2 - 8y

= 8y ( 4y - 1 )

Answer 2

 (16y² - 1) + (1 - 4y)²

= 16y² - 1 + (1)² - (2 x 1 x 4y) + (4y)²

= 16y² - 1 + 1 - 8y + 16y²

= 32y² - 8y

= 8y (4y - 1)

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