Question

find the factors of 2(s – t)square + (s – t) - 1​

Answer 1

Answer:

$2 {(s - t)}^{2} + (s - t) - 1 = 0 \\ 2( {s}^{2} + {t}^{2} - 2st) + s - t - 1 = 0 \\ 2 {s}^{2} + 2 {t}^{2} - 4st + s - t - 1 = 0$