Question

Find the factors of 2(y + 4)^2 + 5(y + 4) - 12.​

Answer 1

Answer:

$(y + 8)(2y + 5) \:$

Step-by-step explanation:

solution---------->

given :-

$2 {(y + 4)}^{2} + 5(y + 4) - 12$

now factorise this we get,

$2 {(y + 4)}^{2} + 5(y + 4) - 12 \\ \\ 2( {y}^{2} + 8y + 16) + 5y + 20 - 12 \\ \\ 2 {y}^{2} + 16y + 32 + 5y + 8 \\ \\ 2 {y }^{2} + 21y + 40 \\ \\ now \: factorise \: this \\ \\ 2 {y}^{2} + 16y + 5y + 40 \\ \\ make \: a \: pair \: n \: take \: common \\ \\ 2y(y + 8) + 5(y + 8) \\ \\ (y + 8)(2y + 5) \\ \\ this \: are \: two \: factors$

Answer 2

Answer:

9y+24 or 3(3y+8)

Step-by-step explanation:

= 2 (y+4)×2+5(y+4)-12

=2×5(y+4)+5(y+4)-12

=4(y+4)+5(y+4)-12

=4y+16+5y+20-12

=9y+36-12

=9y+24

=3(3y+8)