Math, asked by hardikaggarwal1102, 1 year ago

find the factors of 27 + y3

Answers

Answered by Harshadgiri
32

Answer:

Step-by-step explanation:Q..27+y³

→3³+y³

→( a³+ b³ = [a+b] [a² - ab + b²] )

→( 3+y) ( 9 - 3y+y²)

Answered by utsrashmi014
0

Concept

In algebra, a quadratic equation is any equation that can be rearranged into canonical form. Where x represents an unknown number and a, b, and c represent a known number. Where a ≠ 0.

Given

The equation 27+y^3 is given

Find

We have to find the factor given equation

Solution

The steps are as follow:

  • The given equation 27+y^3 can be written as y^3+3^3
  • The y^3+3^3 is can be compared as a^3+b^3
  • a^3+b^3 can we written as (a-b)(a^2+b^2+ab)
  • So by comparing this with y^3+3^3 we get the factor as (y-3)(y^2+9+3y)

Hence the factor of 27 + y^3 will be (y-3)(y^2+9+3y)

#SPJ3

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