Question

find the factors of 32 ,58,96​

Answer 1

Answer:

${\huge{\pink{↬}}} \:  \: {\huge{\underline{\boxed{\bf{\pink{Answer}}}}}}$

Step 1: Since 58 > 32, we apply the division lemma to 58 and 32, to get

58 = 32 x 1 + 26

Step 2: Since the reminder 32 ≠ 0, we apply division lemma to 26 and 32, to get

32 = 26 x 1 + 6

Step 3: We consider the new divisor 26 and the new remainder 6, and apply the division lemma to get

26 = 6 x 4 + 2

We consider the new divisor 6 and the new remainder 2, and apply the division lemma to get

6 = 2 x 3 + 0

The remainder has now become zero, so our procedure stops. Since the divisor at this stage is 2, the HCF of 32 and 58 is 2

Notice that 2 = HCF(6,2) = HCF(26,6) = HCF(32,26) = HCF(58,32) .

Answer 2

Step 1: Since 58 > 32, we apply the division lemma to 58 and 32, to get

58 = 32 x 1 + 26

Step 2: Since the reminder 32 ≠ 0, we apply division lemma to 26 and 32, to get

32 = 26 x 1 + 6

Step 3: We consider the new divisor 26 and the new remainder 6, and apply the division lemma to get

26 = 6 x 4 + 2

We consider the new divisor 6 and the new remainder 2, and apply the division lemma to get

6 = 2 x 3 + 0

The remainder has now become zero, so our procedure stops. Since the divisor at this stage is 2, the HCF of 32 and 58 is 2

Notice that 2 = HCF(6,2) = HCF(26,6) = HCF(32,26) = HCF(58,32) .